Another Penumbra fan and a new poster with his findings on the second umber sequence. I haven't figured what the sought number is but maybe I will give you some ideas. I found some possible patterns but none of them seem to give a perfectly satisfying answer.
8, 6, 9, 6, 11, 8, 13, 10, 15, 8, 11, 4, 9,
If you look at the odd and even number it forms a pattern like this:
ee
oe
oe
oe
oe
o (even=e, odd=o)
It seems too good to be random.
You can divide this to odd and even numbers:
even: 8, 6, 6, 8, 10, 8, 4
odd: 9, 11, 13, 15, 11, 9
First of all, there are 6 even and 5 odd numbers. This implies that the sought number could be odd.
There seems to be a pattern in the odd numbers but it's missing one number, 13. It's one possibility but I don't know what to do with the even numbers if you use it.
9 11 13 15 (13) 11 9
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Another interesting find, addition patterns:
even:
8(-2)6(+0)6(+2)8(+2)10(-2)8(-4)4
The addition pattern is:
-2+0+2+2-2-4
odd:
9(+2)11(+2)13(+2)15(-4)11(-2)9
The addition pattern is:
+2+2+2-4-2
Now when you compare them:
-2+0
+2+2-2-4...
.......
+2+2+2-4-2
It has the same numbers, but the signs don't match exactly.
Still, you could think of it as a loop and move the -2 to the other side
+0
+2+2-2-4-2
....
+2+2+2-4-2
The only number the pattern of the odd numbers is missing is the +0 before it. This would make the first number of the odd pattern 9 (9-0=9) and the signs wouldn't matter. Then the sequence would be:
8,
9, 6, 9, 6, 11, 8, 13, 10, 15, 8, 11, 4, 9,
This would complete the odd/even number pattern like this:
e
oe
oe
oe
oe
oe
o
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So, my suggestion is to try 13 or (especially) 9 as a seed in the decrypting. I don't really understand how it works so I might not be big help with it. It's 3am here so I'm going to bed.