A puzzle

[FlawlessHappiness]

A guy from reddit said this

Door 1: Car
Door 2: Goat
Door 3: Goat

If we don't switch, the chance is 1/3 for all of them.
Here are the outcomes if you switch:

Chooses Door 1, host opens Door 2, you switch. You lose.
Chooses Door 2, host opens Door 3, you switch. You win.
Chooses Door 3, host opens Door 2, you switch. You win.

As you can see you win in 2 of 3 times if you switch.

But it makes no sense to me.
If the host always reveals a wrong door before the final choice, then that door shouldn't even exist.

If there are 3 doors, but my final choice is between 2 of them, why does the third exist, when it has nothing to do with my choice?


The percentages that is shown in the video are from when there are 3 doors to pick from. When there are 3 doors, there are 3 different results. That means the 66% of winning the car, are 66% of 3 different results.

But Mugbill and I don't see 3 doors. We see 2 doors. With 2 doors there are 2 results. That gives us 50% chance of 2 results.


Taking your picture into account



End result
You are only choosing between 2 doors. One with a prize and one without. The last wrong choice is non-existant.