Clever Pictures/Designs

[darkely]

[Robby]

Optical illusion

My honest favourite.

[BAndrew]

Another beautiful thing is this mathematical puzzle.

Using the following number triads and any mathematical symbol you want between them, try to come up with result "6" in each equation. You may not use the digits 0 to 9 except those already given in each equation. Numerical constants such as π, e, etc. are also prohibited.(Hint: There is a solution for each of them)

0 0 0 = 6
1 1 1 = 6
2 2 2 = 6
3 3 3 = 6
4 4 4 = 6
5 5 5 = 6
6 6 6 = 6
7 7 7 = 6
8 8 8 = 6
9 9 9 = 6

[eliasfrost]

0 0 0 = 6

1 1 1 = 6

2 + 2 + 2 = 6

(3x3) - 3 = 6

sqrt4 + sqrt4 + sqrt4 = 6

(5/5) + 5 = 6

6 + 6 - 6 = 6

7 7 7 = 6
8
8 8 = 6

9 9 9 = 6

Those are the only ones I could solve

[Adny]

(7/-7) + 7 = 6

[Statyk]

(7/-7) + 7 = 6

---I did what I did wrong. Ignore that.

[CorinthianMerchant]

WANNA KNOW A CLEVER DESIGN!!!!!!!????

WOMEN!!!!!!!! AHAHAHAHAHAHA

[BAndrew]

0 0 0 = 6

1 1 1 = 6

2 + 2 + 2 = 6

(3x3) - 3 = 6

sqrt4 + sqrt4 + sqrt4 = 6

(5/5) + 5 = 6

6 + 6 - 6 = 6

7 7 7 = 6
8
8 8 = 6

9 9 9 = 6

Those are the only ones I could solve

Correct! Keep it up

(7/-7) + 7 = 6

True.

[MyRedNeptune]

(cos0+cos0+cos0)! = 6
(1+1+1)! = 6
cuberoot8 + cuberoot8 + cuberoot8 = 6
sqrt9 x sqrt9 - sqrt9 = 6

Yay!

[BAndrew]

(cos0+cos0+cos0)! = 6
(1+1+1)! = 6
cuberoot8 + cuberoot8 + cuberoot8 = 6
sqrt9 x sqrt9 - sqrt9 = 6

Yay!

Well done!
note it could be(0! + 0! + 0!)! = 6 instead of (cos0 + cos0 + cos0)! = 6